I hope everyone enjoyed their holidays but back to school tomorrow. Just a few more months you guys!
so for some reason I like to do the inscribe problems.
FORMULA:
a=nr^2 sin 360/2n cos 360/2n
EXAMPLE:
n=3 r=5in
3(5^2) sin 360/10 cos 360/10
*plug into your calculator!
your answer is well i wish i could tell you the answer but my batteries in my calculator are dead and we have none over here. I guess ill be going to the store in the morning before school.
I just have to add I HATE IDENTITIES.
I'm not sure what to talk about since we haven't learned anything new in the past few weeks or been at school. I'm ready to learn so i can have something to blog about.
Sunday, January 2, 2011
Polar.
HAPPY NEW YEARS!
I hope every had a safe and wondersful holiday:)Now its time to re-focus and get ready to begin school again. So here is holiday blog number two i'm sure.
What is Polar.
Chapter eleven is about polar and nonpolar. In section eleven one we learned conversions of polar to noon polar and vice versa. (x,y) coordinates are nonpolar. R and theta coordinates are polar.
X=rcostheta y=rsintheta
The same formula Is used to convert from polar to rectangular.
R=sqrtx^2+y^2
Give polar coordinates for (3,3)
R=sqrt 3^2=3^2
r=sqrt9+9
r=3sqrt2
tan x=3/3
x=tan-1(1) x=45 from trig chart
(3sqrt2,45 degrees)
I hope every had a safe and wondersful holiday:)Now its time to re-focus and get ready to begin school again. So here is holiday blog number two i'm sure.
What is Polar.
Chapter eleven is about polar and nonpolar. In section eleven one we learned conversions of polar to noon polar and vice versa. (x,y) coordinates are nonpolar. R and theta coordinates are polar.
X=rcostheta y=rsintheta
The same formula Is used to convert from polar to rectangular.
R=sqrtx^2+y^2
Give polar coordinates for (3,3)
R=sqrt 3^2=3^2
r=sqrt9+9
r=3sqrt2
tan x=3/3
x=tan-1(1) x=45 from trig chart
(3sqrt2,45 degrees)
#2
Lets take a few steps back to chapter 9! yayyyy.........NOT.
first thing we did was solving right triangles.
SOHCAHTOA
I still suck at these so I won't do any examples :)
sin=opposite/hypotenuse
cos=adjacent/hypotenuse
tan=opposite/adjacent
csc=hypotenuse/opposite
sec=hypotenuse/adjacent
cot=adjacent/opposite
FINDING AREA!
**when you have a right triangle it's super easy!
FORMULA:
1/2(b)(h)
non-right triangles are easy too!
FORMULA:
1/2(a)(b)sin(angle b/w)
LAW OF SINES
-only non-right triangles
-must have an angle and opposite leg value
FORMULA:
sin(angle)/opposite leg=sin(angle2)/opposite leg2
*cross multiply to solve!
LAW OF COSINES
*this one sucks!
-use this when you can't possibly do anything else.
FORMULA:
(opp leg)^2=(adj leg)^2+(adj leg)^2-2(adj leg)(adj leg)cos(angle b/w)
first thing we did was solving right triangles.
SOHCAHTOA
I still suck at these so I won't do any examples :)
sin=opposite/hypotenuse
cos=adjacent/hypotenuse
tan=opposite/adjacent
csc=hypotenuse/opposite
sec=hypotenuse/adjacent
cot=adjacent/opposite
FINDING AREA!
**when you have a right triangle it's super easy!
FORMULA:
1/2(b)(h)
non-right triangles are easy too!
FORMULA:
1/2(a)(b)sin(angle b/w)
LAW OF SINES
-only non-right triangles
-must have an angle and opposite leg value
FORMULA:
sin(angle)/opposite leg=sin(angle2)/opposite leg2
*cross multiply to solve!
LAW OF COSINES
*this one sucks!
-use this when you can't possibly do anything else.
FORMULA:
(opp leg)^2=(adj leg)^2+(adj leg)^2-2(adj leg)(adj leg)cos(angle b/w)
Holiday Blog 1
Holiday Blog 1
So I hope everyone is having a wonderful Christmas holiday, I know I am. This last week is kind of stressful though with me putting all my homework off until the last minute but don’t worry I’ll get it done. Anyway, I forgot my math binder in my locker at school so I’m going to have to blog about some easy stuff that I remember off the top of my head. Chapter seven is super easy stuff so I’m going to work a few problems.
Here are some example problems of the easy stuff you will ever do in advanced math.
Example 1
Convert 39 degrees to radians
39 degrees x π/180 = 13π/60
Example 2
Convert 13π/45 to degrees
13π/45 x 180/π = 2340/45 = 52
Hope everyone enjoys the rest of break! Happy Early New Year! See you guys on Monday January 3, 2011 (: Yayyyy!
So I hope everyone is having a wonderful Christmas holiday, I know I am. This last week is kind of stressful though with me putting all my homework off until the last minute but don’t worry I’ll get it done. Anyway, I forgot my math binder in my locker at school so I’m going to have to blog about some easy stuff that I remember off the top of my head. Chapter seven is super easy stuff so I’m going to work a few problems.
Here are some example problems of the easy stuff you will ever do in advanced math.
Example 1
Convert 39 degrees to radians
39 degrees x π/180 = 13π/60
Example 2
Convert 13π/45 to degrees
13π/45 x 180/π = 2340/45 = 52
Hope everyone enjoys the rest of break! Happy Early New Year! See you guys on Monday January 3, 2011 (: Yayyyy!
#1
Happy new year everyone! I actually miss some of you and can't wait to see ya'll tomorrow. I honestly hope I remember how to even do math since i've been lazy for the past 2 weeks :) Don't you just love last minute blogging? I dont know what to blog about anymore so i'll go back to chapter 7 (the easy chapter)
First week of school.
converting degrees to radians and radians to degrees.
DEGREES TO RADIANS.
multiply by pi/180
EXAMPLE:
15
15xpi/180=15pi.180
simplify!
your answer is pi/12
RADIANS TO DEGREES.
multiply by 180/pi
EXAMPLE:
3pi
3pix180/pi
pi's cancel out.
your answer is 540 degrees.
see how simple this stuff is!
First week of school.
converting degrees to radians and radians to degrees.
DEGREES TO RADIANS.
multiply by pi/180
EXAMPLE:
15
15xpi/180=15pi.180
simplify!
your answer is pi/12
RADIANS TO DEGREES.
multiply by 180/pi
EXAMPLE:
3pi
3pix180/pi
pi's cancel out.
your answer is 540 degrees.
see how simple this stuff is!
Chapter ten/ two
Chapter 10 section 2 is about plugging into one side of the formula when given an another one. They have many different formulas that you will need to learn in order to figure out the problems. Also you will need to know how to find the reference angle and also you will once again need to know your trig chart.
FORMULAS:
tan(alpha+beta)= tanalpha+tanbeta/1-tanalphatanbeta
tan(alpha- beta)= tanalpha-tanbeta/1+tanalphatanbeta
*cot is the reciprocal
i.e. cot(alpha+beta)=1-cotalphacotbeta/cotalpha+cotbeta
ect...
EXAMPLE:
simplify
tan90-tan60/1+tan90tan60
tan(90-60)
tan(30)
answer:squareroot(3)/3
This is how you do section ten dash two. have a great new year :)
FORMULAS:
tan(alpha+beta)= tanalpha+tanbeta/1-tanalphatanbeta
tan(alpha- beta)= tanalpha-tanbeta/1+tanalphatanbeta
*cot is the reciprocal
i.e. cot(alpha+beta)=1-cotalphacotbeta/cotalpha+cotbeta
ect...
EXAMPLE:
simplify
tan90-tan60/1+tan90tan60
tan(90-60)
tan(30)
answer:squareroot(3)/3
This is how you do section ten dash two. have a great new year :)
Chapter nine/ one
FORMULAS TO REMEMBER:
sin= opposite/hypotenuse sec= hypotenuse/adjacent
cos= adjacent/hypotenuse csc= hypotenuse/opposite
tan= opposite/adjacent cot= adjacent/opposite
EXAMPLE:
For triangle ABC
A= 90(degrees) B= 16 a= 34
First, since we already have A and B we need to find C. In order to do that all we are going to do is take 180 (which is the measure of a right triangle) minus 90 your right angle minus 16 the measure of angle B. Which will leave you with 74 and that is angle C.
Next, you have to find b and c. In order to do that you are going to have to take sin, cos, or tan of the angle B using your formula. For this problem you will use sin.
sin= opposite/ hypotnuse
sin 16 degrees= b/34
34sin16= 9.37
Now, you are going to need to find C. You are going to have to use cos= adjacent/ hypotnuse.
cos 16 degrees= c/34
34cos16= 32.68
And that is how you do section 9-1, have a great new year. :)
sin= opposite/hypotenuse sec= hypotenuse/adjacent
cos= adjacent/hypotenuse csc= hypotenuse/opposite
tan= opposite/adjacent cot= adjacent/opposite
EXAMPLE:
For triangle ABC
A= 90(degrees) B= 16 a= 34
First, since we already have A and B we need to find C. In order to do that all we are going to do is take 180 (which is the measure of a right triangle) minus 90 your right angle minus 16 the measure of angle B. Which will leave you with 74 and that is angle C.
Next, you have to find b and c. In order to do that you are going to have to take sin, cos, or tan of the angle B using your formula. For this problem you will use sin.
sin= opposite/ hypotnuse
sin 16 degrees= b/34
34sin16= 9.37
Now, you are going to need to find C. You are going to have to use cos= adjacent/ hypotnuse.
cos 16 degrees= c/34
34cos16= 32.68
And that is how you do section 9-1, have a great new year. :)
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