I had more trouble this week then i did last week. Last week we went over converting degrees to radians and radians to degrees. I found this very easy. For instance, to convert from degrees to radians you simply multiply by pie over 180. Converting radians to degrees you multiply 180 over pie. When we learned how to do word problems I found it difficult at first until I learned my formulas. Reference angles were fairly easy once you figured out which quadrant it was in. You would simply determine whether it was positive or negative and then either subtract 360 or 180.
Example 1) The moon is about 4x10^5km from Earth and its apparent size is about 0.0087 radians. What is the moon's approximate diameter?
-for this problem you must first determine how far the Earth is from the moon, its apparent size, and the approximate diameter.
theta=0.0087 radius=4x10^5
s=?
*first choose which formula would be best to work this problem.
s=rtheta
k=1/2r^2theta
k=1/2rs
*s=rtheta would be the best formula to use.
*set it up s=(4x10^5)(0.0087)
*multiply (4x10^5) and (0.0087)
-when plugging it into your calculator it should be 4xE5 x 0.0087
*simply multiply both numbers together
**your answer should be s=3480km
I pretty much understood everything we went over last week. But i'm having trouble with a few things from this past week. I'm still a little iffy on the 5 trig function. I'm not sure how you find the hypotenuse. Inverse of angle is still confusing be a bit too.
Kaitlyn to find the hypotenuse you need to plug into the pythagorean theorem.
ReplyDeletehypotenuse ^ 2 = side ^ 2 + side ^ 2
Be sure to ask questions in class this week to get back on track.