6-3

This week in advanced math we learned how to find parts of the equation. The equation has many parts and we learned how to identify them all. We also learned recently how to find the equation of the circle. This is done by finding the distance formula and plugging numbers in the right place into the equation. But in this we'll focus on 6-3 and finding parts of the equation.

In the form x^2/a + y^2/b = 1

Parts of the equation

x^2/9 + y^2/16 = 1

major axis- y

minor axis- x

length of major-2 the square root of 16 = 2(4)= 8

length of minor- 2 the square root of 9 = 2(3) = 6

vertex - (0,4) and (0,-4)

other int - (3,0) and (-3,0)

focus - 9-16 = f^2 -7=f^2 f= square root of -7