This week we did Aleks a lot. Aleks is great. Every time I get a problem right it tells me how great I am and its a good motivater. We need to spend more CLASS time doing Aleks, not just home time. It wouldn't be so bad for at home but 10 units is a lot B-Rob. I don't really remember what we did to much this week so i'll just put my notes from section 12-1 up hear. BTW we had baseball on Superbowl Sunday which is ridiculous.
vectors represent motion
they have a magnitude and direction.
to add vectors you add head to tail.
the triangle formed by the vectors is your result.
to add vectors algebraically you add the components.
Sunday, February 6, 2011
This week we continued to work on aleks.com. I love aleks because i can work at my own pace and i'm learning a lot. We finished up chapter 14 on matrices (which i absolutely love). Now we are working on vectors. chapter 12-1 and 12-2.
12-1
VECTORS-represent motion
they have a magnitude and direction.
-to add vectors you add head to tail.
-the triangle formed by the vectors is your result.
-to add vectors algebraically you add the components.
12-2
-to find the magnitude
**square root of x^2+y^2
-scalar multiplication puts a scalar times each component.
-you are given 2 points (A&B)
**A&B=(x2-x1;y2-y1)
^^^^remember this from algebra 2!
*it's hard to do examples for 12-1 since they are graphs drawn.
Now im going to spread my love for aleks.com
it is a whole lot easier than doing 2 blogs per week.
im learning from the stupid mistakes i usually do.
its fun?
*i think as a class we all enjoy it. (especially when we do that in class)
byeeeeeeeeeeeeeeee.
12-1
VECTORS-represent motion
they have a magnitude and direction.
-to add vectors you add head to tail.
-the triangle formed by the vectors is your result.
-to add vectors algebraically you add the components.
12-2
-to find the magnitude
**square root of x^2+y^2
-scalar multiplication puts a scalar times each component.
-you are given 2 points (A&B)
**A&B=(x2-x1;y2-y1)
^^^^remember this from algebra 2!
*it's hard to do examples for 12-1 since they are graphs drawn.
Now im going to spread my love for aleks.com
it is a whole lot easier than doing 2 blogs per week.
im learning from the stupid mistakes i usually do.
its fun?
*i think as a class we all enjoy it. (especially when we do that in class)
byeeeeeeeeeeeeeeee.
14-3
This week in advanced math we finished up chapter 14 and took a test and now we are currently working on chapter 12. Chapter 12 is about vectors but I am going to show you how to take the inverse of a matrix today. This is probably one of the easiest things to do when it comes to matricies. Here is how you find an inverse of a matrix.
1. First you are going to want to switch the first number of the matrix with the fourth number.
2. Then make the second and third numbers opposite of their sign.
3. Then cross multiply your origional matrix and find the determinate.
4. Take your determinate and multiply it by your second matrix.
EXAMPLE:
1. [2 3
1 4]
[4 -3
-1 2]
(4x2-1x3)= 5
1/5[4 -3
-1 2]
[4/5 -3/5
-1/5 2/5] This is your answer.
This is the easiest way to do this just follow the steps and you should be fine.
1. First you are going to want to switch the first number of the matrix with the fourth number.
2. Then make the second and third numbers opposite of their sign.
3. Then cross multiply your origional matrix and find the determinate.
4. Take your determinate and multiply it by your second matrix.
EXAMPLE:
1. [2 3
1 4]
[4 -3
-1 2]
(4x2-1x3)= 5
1/5[4 -3
-1 2]
[4/5 -3/5
-1/5 2/5] This is your answer.
This is the easiest way to do this just follow the steps and you should be fine.
12-1,12-2
This week we learned some sections in chapter 12. In 12-1 and 12-2 we learned about vectors and how to represent it.
Vectors-represent motion and it has a magnitude and a direction.
*to add vectors you add head to tail.
the triangle formed by the vectors give the resultant vector.
another thing is to add vector algebraically you add components.
-to find the magnitude
square root of x^2+y^2 magnitude is done as |->|
Ex: A(4,2) B(9,-1) find on top of AB is ->
on top of AB ->(9-4,-1-2)=(5,-3)is on top of AB ->
find the magnitude of on top of AB ->
square root of 5^2+-3^2= square root of 34
Ex: find |on top of AB ->| if A(1,3) B(2,4)
on top of AB -> = 2-1,4-3= (1,1)
|on top of AB ->| Square root of 1^2+1^2= square root of 2.
If you know all your rules and stuff sections 12-1 and 12-2 will be easy for u.
Vectors-represent motion and it has a magnitude and a direction.
*to add vectors you add head to tail.
the triangle formed by the vectors give the resultant vector.
another thing is to add vector algebraically you add components.
-to find the magnitude
square root of x^2+y^2 magnitude is done as |->|
Ex: A(4,2) B(9,-1) find on top of AB is ->
on top of AB ->(9-4,-1-2)=(5,-3)is on top of AB ->
find the magnitude of on top of AB ->
square root of 5^2+-3^2= square root of 34
Ex: find |on top of AB ->| if A(1,3) B(2,4)
on top of AB -> = 2-1,4-3= (1,1)
|on top of AB ->| Square root of 1^2+1^2= square root of 2.
If you know all your rules and stuff sections 12-1 and 12-2 will be easy for u.
Sections 12-1 and 12-2
This week in advanced math we took our test on Wednesday instead of Tuesday because we got out of school early due to the weather. The test was super easy so hopefully I got a good grade. Since we took the test on Wednesday we had to double up on learning sections in chapter 12. Sections 12-1 and 12-2 are on vectors. Vectors represent motion. They have a magnitude and a direction.
To add vectors you add the head and the tail. To add vectors algebracically you add the components.
The triangle formed by the vectors give the resultant vector.
To find the magnitude square root x2 + y2 magnitude is done as | -> |
Scalar multiplication puts a scalar times each component.
Given 2 points A and B
->
AB = (x2 – x1 y2 –y1)
Geometric Representation
Find c + d
Connect the head of C to the tail of D.
Find 2s
Connect the head of S to another tail of S.
Find –p
Reverse the p and draw it in the opposite direction.
This week in advanced math we took our test on Wednesday instead of Tuesday because we got out of school early due to the weather. The test was super easy so hopefully I got a good grade. Since we took the test on Wednesday we had to double up on learning sections in chapter 12. Sections 12-1 and 12-2 are on vectors. Vectors represent motion. They have a magnitude and a direction.
To add vectors you add the head and the tail. To add vectors algebracically you add the components.
The triangle formed by the vectors give the resultant vector.
To find the magnitude square root x2 + y2 magnitude is done as | -> |
Scalar multiplication puts a scalar times each component.
Given 2 points A and B
->
AB = (x2 – x1 y2 –y1)
Geometric Representation
Find c + d
Connect the head of C to the tail of D.
Find 2s
Connect the head of S to another tail of S.
Find –p
Reverse the p and draw it in the opposite direction.
Saturday, February 5, 2011
14-3
Here's my weekend bloggggg:
This week we finished Chapter 14 and tested on it. Along with that we continued to work on Aleks and even started Chapter 12 which had to do with vectors. I’m going to explain the concept of finding an inverse in a matrix.
EXAMPLE 1: Given A= [4 3 find its inverse.
2 6]
A). To find an inverse, flip the 1st number on the top row and the 2nd on the bottom (4 and 6) and make the 2nd number on the first row and 1st on the second row negative (-3 and -2).
B). Your new matrix should look like this [6 -3
-2 4]
C). Now cross multiply your original matrix and subtract (4 x 6 – 2 x 3) = 18
D). Mutiply your new matrix by the determinant, which is 1/18.
E). Your answer is [1/3 -1/6
-1/9 2/9]
I know this is a little short but I've been doing Aleks all morning and I'm really frustrated :/ sorry!
This week we finished Chapter 14 and tested on it. Along with that we continued to work on Aleks and even started Chapter 12 which had to do with vectors. I’m going to explain the concept of finding an inverse in a matrix.
EXAMPLE 1: Given A= [4 3 find its inverse.
2 6]
A). To find an inverse, flip the 1st number on the top row and the 2nd on the bottom (4 and 6) and make the 2nd number on the first row and 1st on the second row negative (-3 and -2).
B). Your new matrix should look like this [6 -3
-2 4]
C). Now cross multiply your original matrix and subtract (4 x 6 – 2 x 3) = 18
D). Mutiply your new matrix by the determinant, which is 1/18.
E). Your answer is [1/3 -1/6
-1/9 2/9]
I know this is a little short but I've been doing Aleks all morning and I'm really frustrated :/ sorry!
Wednesday, February 2, 2011
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