This week we learned a section in chapter 5 which deals with rational exponents. This section is a easy and not that hard at all.
Formulas:
A(t)=A0b^(t/k)
-A0 is starting point
-b is halfing, doubling, ect
-t is time and k is time it takes to get to b
Examples:
3rd root of square root of x= x^1/3
(16/100)^1/2= square root of 16/square root of 100 which can be simplified to 2/5
27^2x=3^2
(3^3)^2x=3^2
3^6x=3^2
6x=2
x=1/3
Basically if you know your rules and the formula this section will be easy..
Sunday, February 27, 2011
chapter 5
This week we learned things from chapter 5 and completed a lot of aleks modules. 5 was about exponents and a couple formulas. Unfortunately, exponents are not the easiest thing for me which is why I think I did so much worse in algebra II. Since I’m not very good at those, I’ll do a formula example.
The first formula we did was the easiest for me. It is:
A(t) = Ao (1 + r)^t
This formula is used with word problems when given a percent, time and rate.
Ao= your starting number
R= the rate
T= time
After you read the problem, you plug in the numbers to the formula, type it in your calculator, and it gives you the answer. (percents must be changed to decimals)
Ex: Suppose you have $1,000 dollars invested at a 7% interest rate. How much money will you have after 2 years?
A(t) = $1,000 (1 + .07)^2
^^ plug that into your calculator and you get $1144.90 as your answer.
The first formula we did was the easiest for me. It is:
A(t) = Ao (1 + r)^t
This formula is used with word problems when given a percent, time and rate.
Ao= your starting number
R= the rate
T= time
After you read the problem, you plug in the numbers to the formula, type it in your calculator, and it gives you the answer. (percents must be changed to decimals)
Ex: Suppose you have $1,000 dollars invested at a 7% interest rate. How much money will you have after 2 years?
A(t) = $1,000 (1 + .07)^2
^^ plug that into your calculator and you get $1144.90 as your answer.
Chapter 5
This week in advanced math we had to complete seven aleks modules and this weekend we have to do fourteen. I finished both so I’m super glad. Mrs. Robinson wasn’t here for a few days but we did manage to start chapter five. We were also supposed to get packets this week for our exam this Friday. However, considering the circumstances that happened this week Mrs. Robinson changed the exam to just chapter five. Chapter five is about exponents. We covered a few sections in five and it is pretty easy stuff. We learn how to solve exponents and we used 3 different formulas. Let’s do some example problems.
Solve the following problems:
Example 1:
7-2 = 1/49
Example 2:
(-7)-2 = -1/49
Example 3:
When given a chart you must pick one of the following formulas:
Read the problem, plug in the numbers, and then into your calculator and get an answer.
A(t) = Ao (1+r)2
A(t) = Ao b t/k
P(t) = Po ert
Solve the following problems:
Example 1:
7-2 = 1/49
Example 2:
(-7)-2 = -1/49
Example 3:
When given a chart you must pick one of the following formulas:
Read the problem, plug in the numbers, and then into your calculator and get an answer.
A(t) = Ao (1+r)2
A(t) = Ao b t/k
P(t) = Po ert
Rational Exponents
This week in advanced math I think it is chapter 5 which we are working on. One of the sections we are doing is called rational exponents. This is not to difficult I will show you how to do some of these kinds of problems.
FORMULAS:
A(t)=A0b^(t/k)
A0 is starting point
b is halfing, doubling, ect
t is time and k is time it takes to get to b
Exponents that involve roots.
EXAMPLE:
5th root of (3)^3
3^3/5
(4/16)^1/2
2/4 which is equal to 1/2
*This is the easiest way to explain rational exponents.
FORMULAS:
A(t)=A0b^(t/k)
A0 is starting point
b is halfing, doubling, ect
t is time and k is time it takes to get to b
Exponents that involve roots.
EXAMPLE:
5th root of (3)^3
3^3/5
(4/16)^1/2
2/4 which is equal to 1/2
*This is the easiest way to explain rational exponents.
this past week was the worst week of school ever. we learned about rational exponents. these are very easy and we've seen this in aleks. everything we did this week was referred to aleks. so here are a few examples of stuff.
EXAMPLE:
6square root of x^3--------x^3/6
FORMULAS:
a(t)=a0(1+r)^t
0---is your starting point
r---is your decimal
t---is your time
*when given a word problems you can easily plug it into the formula. once you have it plugged into your formula you can then put it in your calculator to get your final answer. It's really simple so i hope we have a good bit of these on our 9 weeks exam friday :)
i've still been trying to do aleks but it keeps kicking me off my computer. i am learning with using aleks.
EXAMPLE:
6square root of x^3--------x^3/6
FORMULAS:
a(t)=a0(1+r)^t
0---is your starting point
r---is your decimal
t---is your time
*when given a word problems you can easily plug it into the formula. once you have it plugged into your formula you can then put it in your calculator to get your final answer. It's really simple so i hope we have a good bit of these on our 9 weeks exam friday :)
i've still been trying to do aleks but it keeps kicking me off my computer. i am learning with using aleks.
Exponents
This was a hectic week in school and advanced math. We learned about all kinds of exponents and how to change them from exponents to radicals and vise versa. We did a lot in Aleks, and we had a lot of homework this week. We also learned about rational exponents, which are exponents that involve roots. This was pretty easy with just the numbers. We we inserted letters it took me a little while to get the hang of it, but I figured it out. I enjoyed Rational Exponents better than the T1 formula so here you go.
Rational Exponents
Ex. (49/81)^1/2
1) (49^1/2)/(81^1/2)
2)(square root of 49/ square root of 81)
3)7/9
5-4
Almost forgot about this! This week in Advanced Math we learned about exponents and formulas involving percent, rate, and time. Section 5-4 involved one formula – P(t)=Pe^r*t
P – starting amount
e – on calculator (e is approximately 2.7)
r – rate as a decimal
t – time
EXAMPLE 1: Suppose $2,000 is invested at 5% interest compounded continuously. How much money do you have after 3 years?
A). Using the formula, plug in the information given.
P=2,000(starting amount)e^(0.5*3)
B). By plugging all of that into your calculator, you get $8963.38 as your final answer.
EXAMPLE 2: Which has a larger value? e^square root of 3 or 3^e
A). The answer to this problem can be achieved by plugging the two into your calculator.
B). e^square root of 3 = 5.65 and 3^e = 19.81
C). Therefore, the first one has a larger value.
This is a little short but my computer is installing new updates and it’s counting down to shutdown!
Almost forgot about this! This week in Advanced Math we learned about exponents and formulas involving percent, rate, and time. Section 5-4 involved one formula – P(t)=Pe^r*t
P – starting amount
e – on calculator (e is approximately 2.7)
r – rate as a decimal
t – time
EXAMPLE 1: Suppose $2,000 is invested at 5% interest compounded continuously. How much money do you have after 3 years?
A). Using the formula, plug in the information given.
P=2,000(starting amount)e^(0.5*3)
B). By plugging all of that into your calculator, you get $8963.38 as your final answer.
EXAMPLE 2: Which has a larger value? e^square root of 3 or 3^e
A). The answer to this problem can be achieved by plugging the two into your calculator.
B). e^square root of 3 = 5.65 and 3^e = 19.81
C). Therefore, the first one has a larger value.
This is a little short but my computer is installing new updates and it’s counting down to shutdown!
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