Sunday, September 26, 2010

Chapter 9 in Advanced Math brings us back to Geometry. We learned how to fine the unknown side of the right triangle. The key to this section is to remember SOHCAHTOA.

SOHCAHTOA
sin=opposite/hypotenuse
cos=adjacent/hypotenuse
tan=opposite/adjacent
csc=hypotenuse/opposite
sec=hypotenuse/adjacent
cot-adjacent/opposite


EXAMPLE 1: For triangle ABC, C=90 degrees, A=26 degrees, and a=38
1). Since we know angles A and C, let’s solve for B. Subtract 90 degrees and 26 degrees from 180 degrees to get your answer. Angle C = 64 degrees. Now we have all of our angles.
2). We are given angle A, so to solve for b and c use the functions above. To solve for c, use sin which is opp/hyp - sin 26 degrees = 38/c
3). Multiply both sides by c and continue solving - c = 86.684 degrees
4). Now that we have a and c, we need to solve for b. We will use tan which is opp/adj - tan 26 degrees = 38/b.
5). Multiply both sides by b and continue solving - b = 77.911 degrees


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