4-2

This week we went back to chapter 4 in the book which is algebra 2. For 4-2,we learned how to solve for f and g of (x). I pretty much remembered it from last year, but as with anything else, when I go to do it on my own, I get lost. So, like always, there are formulas to remember:

A composition function is a function inside of another function. Such as f(x).
These are the formulas:

Sum- (f+g)(x)=f(x)+g(x)
Difference- (f-g)(x)=f(x)-g(x)
Product- (f*g)(x)=f(x)*g(x)
Quotient- (f/g)(x)=f(x)/g(x)

The variable inside of the parenthesis is where you plug in what you are told into the equation. I think the problems are a bit simpler than the directions make it seem. All you really are doing is plugging in numbers into an equation that is already there and solving.

Ex. (sum)
f(x) = 3x + 5 g(x) = 9x + 8
Since it says to do the sum formula, you find it up at the top and plug in the equations where it tells you to.
(f+ g)(x) = (3x + 5) + (9x + 8)
Simply solve.
12x + 13